[LeetCode] Remove Duplicates from Sorted Array II

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Follow up for "Remove Duplicates".

What if duplicates are allowed at most twice?

For example,

Given sorted array A=[1, 1, 1, 2, 2, 3]

Your function should return length = 5, and A is now[1,1,2,2,3]

ideas: Similar idea with the previous one. Check the A[0] with A[2] if not equal, then assign the value back, or, go the next loop

 

class Solution {public:    int removeDuplicates(int A[], int n) {        if(n <= 2 ) return n;                int j = 2;        for(int i = 2 ; i < n; i++)        {            if(A[j - 2] != A[i])            {                A[j++] = A[i];            }        }                return j;    }};

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