ACM路程----1085 A+B for Input-Output Practice (I)

题目描述：

Your task is to Calculate a + b. Too easy?! Of course! I specially designed the problem for acm beginners. You must have found that some problems have the same titles with this one, yes, all these problems were designed for the same aim

输入：

The input will consist of a series of pairs of integers a and b, separated by a space, one pair of integers per line.

输出：

For each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input.

样式输入：

1 5

10 20

样式输出：

6

30

代码如下：

#include<stdio.h>
int main()
{
 int a,b;
 while(scanf("%d %d",&a,&b)!=EOF)
 printf("%d\n",a+b);
 return 0;
}