1432 Decoding Morse Sequences
来源:互联网 发布:关键词优化有什么用 编辑:程序博客网 时间:2024/05/01 04:16
Description
Before the digital age, the most common "binary" code for radio communication was the Morse code. In Morse code, symbols are encoded as sequences of short and long pulses (called dots and dashes respectively). The following table reproduces the Morse code for the alphabet, where dots and dashes are represented as ASCII characters "." and "-":
Input
The first line of the input contains exactly one positive integer d equal to the number of data sets, 1 <= d <= 20. The data sets follow.
The first line of each data set contains a Morse sequence - a nonempty sequence of at most 10 000 characters "." and "-" with no spaces in between.
The second line contains exactly one integer n, 1 <= n <= 10 000, equal to the number of words in a dictionary. Each of the following n lines contains one dictionary word - a nonempty sequence of at most 20 capital letters from "A" to "Z". No word occurs in the dictionary more than once.
Output
The output should consist of exactly d lines, one line for each data set. Line i should contain one integer equal to the number of distinct phrases into which the Morse sequence from the i-th data set can be parsed. You may assume that this number is at most 2 * 10^9 for every single data set.
Sample Input
Sample Output
Source
Central Europe 2001
**********************************************************************************
*************************************************************************************
#include<stdio.h>#include<string.h>char Morse[26][5]={".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."};int best[10001],n,len;char s[10001],dic[10001][30],word[10001][101];void init(){int i,j;memset(word,'/0',sizeof(word));for(i=0;i<n;i++) for(j=0;j<strlen(dic[i]);j++) strcat(word[i],Morse[dic[i][j]-'A']);memset(best,0,sizeof(best));best[0]=1;//for(i=0;i<n;i++)// printf("%s/n",word[i]);}void DP(){int i,j,k,flag;for(i=0;i<=len;i++) if(best[i]) for(j=0;j<n;j++) { flag=1; for(k=0;k<strlen(word[j]);k++) { if(i+k==len)break; if(s[i+k]!=word[j][k]){flag=0;break;} } if(flag)best[i+strlen(word[j])]+=best[i]; }printf("%d/n",best[len]);}int main(){int cas,i;scanf("%d",&cas);while(cas--){ scanf("%s%d",s,&n); len=strlen(s); for(i=0;i<n;i++) scanf("%s",dic[i]); init(); DP();}}
2
1.---.--.-.-.-.---...-.---.6ATTACKTICKATTACKDAWNDUSK
Notice that in the absence of pauses between letters there might be multiple interpretations of a Morse sequence. For example, the sequence -.-..-- could be decoded both as CAT or NXT (among others). A human Morse operator would use other context information (such as a language dictionary) to decide the appropriate decoding. But even provided with such dictionary one can obtain multiple phrases from a single Morse sequence.
Task
Write a program which for each data set:
reads a Morse sequence and a list of words (a dictionary),
computes the number of distinct phrases that can be obtained from the given Morse sequence using words from the dictionary,
writes the result.
Notice that we are interested in full matches, i.e. the complete Morse sequence must be matched to words in the dictionary.
- 1432 Decoding Morse Sequences
- poj 1432 Decoding Morse Sequences
- POJ 1432 Decoding Morse Sequences
- [ZOJ 1387] [POJ 1432] Decoding Morse Sequences
- 1387 Decoding Morse Sequences
- HDU 1523 Decoding Morse Sequences
- HDU 1523 Decoding Morse Sequences(DP)
- morse
- sequences
- Sequences
- Huffman&Morse
- Morse code
- Huffman decoding.
- encoding / decoding
- UVa11541 - Decoding
- Message Decoding
- Message Decoding
- F - Decoding
- 设置OpenGL编程环境
- 1597
- 1519 Digital Roots
- 1503 Integer Inquiry
- 1468 Rectangles
- 1432 Decoding Morse Sequences
- JBuilder中使用SQL server 2000时的配置步骤
- 1313 Booklet Printing
- 1251 Jungle Roads
- 浅谈数据库设计技巧(转经典)
- 1239 Increasing Sequences
- 网站栏目
- 1176 Party Lamps
- 1182 食物链