Linux如何获取循环日期

1. #!/bin/bash
   
2. startDate=2010-05-02
   
3. endDate=2010-08-03
   
4. startSec=`date -d "$startDate" "+%s"`
   
5. endSec=`date -d "$endDate" "+%s"`
   
6. for((i=$startSec;i<=$endSec;i+=86400))
   
7. do
   
8.     date -d "@$i" "+%Y-%m-%d"
   

1. done

1. i=0
   
2. until [[ $day == "2010-08-03" ]]
   
3. do
   
4.         day=$(date -d "2010-05-02 $i days" +%Y-%m-%d)
   
5.         echo $day
   
6.         ((i++))
   
7. done