1的平方加到n的平方

#include <cstdio>#include <cstdlib>#include <cstring>#include <algorithm>#include <iostream>#include <cmath>#include <queue>#include <map>#include <stack>#include <list>#include <vector>#include <ctime>#define LL __int64#define eps 1e-8using namespace std;int main(){LL n; while (~scanf("%lld",&n)){LL ans1=n*(n+1)*(2*n+1)/6;//1的平方加到n的平方 LL ans2=(n*(n+1)/2)*(n*(n+1)/2);////1的立方加到n的立方 printf("%lld %lld\n",ans1,ans2); }return 0;}