printf 和scanf的%*s, %*d的作用

#include<stdio.h>int main(){        int i;        char str[1024];        printf("Enter text: ");        scanf("%*s", &str);        printf("%s\n", str);        printf("Enter interger: ");        scanf("%*d", &i);        printf("%d\n", i);        return 0;}

输出

manav@workstation:~$ gcc -Wall -pedantic d.cd.c: In function ‘main’:d.c:8: warning: too many arguments for formatd.c:12: warning: too many arguments for formatmanav@manav-workstation:~$ ./a.outEnter text: manavDEnter interger: 12345372manav@workstation:~$

scanf 中使用*d是跳过的意思

int a=1,b=2,c=3;    scanf("%d %*d %d",&a,&b,&c); //input is given as: 10 20 30

结果是

a=10 b=30 and c=3;  // 20 is skipped

再比如:

<pre name="code" class="cpp">scanf("#%f:%*d:%*d:%*d\n", &num[0]);//#1.33:3:4:5

结果就是num[0] = 2.33

注:原文来自 http://stackoverflow.com/questions/2155518/what-is-scanfs-and-scanfd-format-identifiers