c语言实现不同类型数组的print(union + flag)

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#include <stdio.h>#include <stdlib.h>#include <string.h>union ArrayType {int *d;double *lf;char *c;};enum DATATYPE {CHAR= 'c',DOUBLE= 'l',INT = 'd'};struct ArrayType2 {enum DATATYPE flag;union {int *d;double *lf;char *c;};};void printArray(struct ArrayType2 array,int n){int i;int sizea = n;int flag = array.flag;switch(flag) {case 'd':for (i = 0; i < sizea; ++i) {                printf("%d%c", array.d[i], i == sizea-1 ? '\n':'\t');}break;case 'l':for (i = 0; i < sizea; ++i) {                printf("%lf%c", array.lf[i], i == sizea-1 ? '\n':'\t');}break;case 'c':for (i = 0; i < sizea; ++i) {                printf("%c%c", array.c[i], i == sizea-1 ? '\n':'\t');}break;default:printf("invalid data type input");exit(-1);break;}}void printArray2(void *val, int n, char flag){        int i;        int sizea = n + 1;union ArrayType a;switch(flag) {case 'd':a.d = (int *)val;for (i = 0; i < sizea; ++i) {                printf("%d%c", a.d[i], i == sizea-1 ? '\n':'\t');}break;case 'a':a.lf = (double *)val;for (i = 0; i < sizea; ++i) {                printf("%lf%c", a.lf[i], i == sizea-1 ? '\n':'\t');}break;case 'c':a.c = (char *)val;for (i = 0; i < sizea; ++i) {                printf("%c%c", a.c[i], i == sizea-1 ? '\n':'\t');}break;default:break;}}int main(){struct ArrayType2 type_int;struct ArrayType2 type_double;int a[] = {1, 3, 5, 6};double d[] = {3.5, 3.22, 54.4};type_int.flag = INT;type_int.d = a;printArray(type_int, sizeof(a)/sizeof(int));type_double.flag = DOUBLE; type_double.lf = d;printArray(type_double, sizeof(d)/sizeof(double));return 0;}
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