HDU5138 CET-6 test && BestCoder Round #21 1001
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题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5138
解题思路:BestCoder官方题解:
直接从1到n枚举i,判断n-i是否与1,2,4,7,15相等复杂度o(n)水题,直接上代码:
AC代码:
#include<iostream>#include<cstdio>using namespace std;int main(){ int n; int b[]={1,2,4,7,15}; while(scanf("%d",&n)!=EOF) { int i,j=0,t=n,a[5]; for(i=0;i<5;i++) { if(n-b[i]<1) break; a[i]=n-b[i]; } for(i--;i>0;i--) printf("%d ",a[i]); printf("%d\n",a[i]); } return 0;}
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