sql 生成树型样式

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<pre name="code" class="sql">--根据父节点,搜索下面的子节点包括父节点WITH  TREE  as (select *,0 as lvl,cast('' as varchar(100)) as t from YZ_department where id ='ac4345cb-c1aa-487e-9380-d2b64e3c85ad'union all select a.*,lvl+1,cast(t+'    ' as varchar(100)) as t from YZ_department a ,TREE where tree.id  = a.parentid)select id,parentid,lvl,t+name name from TREE


                                             
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