hdu 2014

水题

AC代码：

#include <stdio.h>int main(){    int i,n,a[100];    while(scanf("%d",&n)!=EOF)    {    int max=0,min=99999999,sum=0;    for(i=1;i<=n;i++)        {            scanf("%d",&a[i]);            sum+=a[i];            if(a[i]>max)  max=a[i];            if(a[i]<min)  min=a[i];        }    printf("%.2lf\n",(sum-max-min)*1.0/(n-2));    }    return 0;}