LeetCode:Swap Nodes in Pairs
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Given a linked list, swap every two adjacent nodes and return its head.
For example,
Given 1->2->3->4
, you should return the list as 2->1->4->3
.
Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed.
// Source : https://oj.leetcode.com/problems/swap-nodes-in-pairs/// Author : Chao Zeng// Date : 2014-12-21struct ListNode { int val; ListNode *next; ListNode(int x) : val(x),next(NULL) {}};class Solution{public: ListNode *swapPairs(ListNode *head){ if (!head) return NULL; ListNode *phead = head; int length = 0; while (phead){ phead = phead->next; length++; } if (length == 1) return head; ListNode *first = head; ListNode *second = head->next; while (first && second){ int elem = first->val; first->val = second->val; second->val = elem; first = second->next; if (first != NULL) second = first->next; else break; } return head; }};
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