android listview中自定义适配器和复选框

来源：互联网发布：网络安全技术的重要性编辑：程序博客网时间：2024/05/17 23:45

下面的代码中报错了，代码如下

@Overrideppublic View getView(final int position, final View convertView, final ViewGroup parent) {      final ViewHolder viewHolder;      View view = convertView;      if (view == null) {          view = LayoutInflater.from(mContext).inflate(R.layout.row, parent, false);          viewHolder = new ViewHolder();           viewHolder.textTitle = (TextView) view.findViewById(R.id.title);          viewHolder.checkBox = (CheckBox) view.findViewById(R.id.checkBox);           viewHolder.checkBox.setTag(position);          view.setTag(viewHolder);           viewHolder.imageView = (ImageView) view.findViewById(R.id.activity_googlecards_card_imageview);      } else {          viewHolder = (ViewHolder) view.getTag();          viewHolder.checkBox.getTag(position);      }       viewHolder.textTitle.setText(getItem(position).getTitle());       viewHolder.checkBox.setChecked(myIntegerArrayList.contains(position));      viewHolder.checkBox.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {          @Override          public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {              if (isChecked) {                  myIntegerArrayList.add(position);              } else {                  myIntegerArrayList.remove((Object) position);              }          }      });       return view;}}    private static class ViewHolder {      TextView textTitle;      CheckBox checkBox;}}

该复选框本身工作正常。位置正确添加到我的ArrayList，但如果（假设我选中的项目在位置1）我把listview滚动到底部，然后再滚回去，选中取消了....

处理方法

删掉代码viewHolder.checkBox.setTag(position);
把 viewHolder.checkBox.getTag();放到 onCheckedChanged 中，你按照下面的代码改动

@Overridepublic View getView(final int position, final View convertView, final ViewGroup parent) {      final ViewHolder viewHolder;      View view = convertView;      if (view == null) {          view = LayoutInflater.from(mContext).inflate(R.layout.row, parent, false);          viewHolder = new ViewHolder();           viewHolder.textTitle = (TextView) view.findViewById(R.id.title);          viewHolder.checkBox = (CheckBox) view.findViewById(R.id.checkBox);            view.setTag(viewHolder);           viewHolder.imageView = (ImageView) view.findViewById(R.id.activity_googlecards_card_imageview);      } else {          viewHolder = (ViewHolder) view.getTag();          viewHolder.checkBox.getTag(position);      }      viewHolder.checkBox.setTag(position);       viewHolder.textTitle.setText(getItem(position).getTitle());       viewHolder.checkBox.setChecked(myIntegerArrayList.contains(position));      viewHolder.checkBox.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {          @Override          public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {              if (isChecked) {                  myIntegerArrayList.add(viewHolder.checkBox.getTag());              } else {                  myIntegerArrayList.remove((Object) viewHolder.checkBox.getTag());              }          }      });       return view;}}

让你删掉 viewHolder.checkBox.setTag(position); 是为了回收ListView,你需要报错位置在tag中，并让 onCheckedChanged 获得到

添加viewHolder.checkBox.getTag() 也是同样的原因

原文地址：http://www.itmmd.com/201411/119.html
该文章由萌萌的IT人整理发布,转载须标明出处。

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