hdoj1012

u Calculate e
Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 32449    Accepted Submission(s): 14550

 

Problem Description

A simple mathematical formula for e is

 

where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.

 

Output

Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.

 

Sample Output

n e
- -----------
0 1
1 2
2 2.5
3 2.666666667
4 2.708333333

 #include<stdio.h>
//#include<math,h>
int main()
{
 int i;
 double f[20];
 int s[20];
 f[0]=1;s[0]=1;s[1]=1;
 for(i=1;i<=9;i++)
 {
  s[i]=i*s[i-1];
  f[i]=f[i-1]+1/(double)(s[i]);
 }
 printf("n e\n");
 printf("- -----------\n");
 printf("0 1\n");
 printf("1 2\n");
 printf("2 2.5\n");
 for(i=3;i<=9;i++)
 {
 printf("%d %.9lf\n",i,f[i]);
 }
 return 0;
}