UVA - 10071 Back to High School Physics(高中物理)
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一个粒子具有初速度和恒定的加速度,给定t 时刻粒子的速度,求2×t 时间粒子的位移。
结论:匀加速直线运动的平均速度等于初速度与末速度和的一半。 位移 = v平×t。
因为 x=v0*t+1/2*a*t*t v=v0+at; 得出 平均速度 v平= x/t =v0+1/2*a*t =(v+v0)/2;
那么 2×t 时刻 粒子位移 x= (v0+a*2t +v0) /2 *2*t = 2*t (v0+a*t) =2*v*t
#include<cstdio>int main(){ int a,b; while(~scanf("%d%d",&a,&b)) { printf("%d\n",2*a*b); } return 0;}
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