输出1000-2000之间的润年

#include<stdio.h>#define IS_LEAP ((year % 4 == 0) && (year % 100) != 0) ||(year % 400) == 0//判断1000-2000之间的闰年void func(){int year = 1000;for(year=1000;year<=2000;year+=4){if(IS_LEAP){ printf("%d ",year);}}    printf("\n");}int main(){func();return 0;}