用结构体数组存储30名学生的学号，…

来源：互联网发布：java编程实例大全编辑：程序博客网时间：2024/05/22 15:12

# include "stdio.h"
# define N 30
struct fengshu
{
int chinese;
int math;
int english;
int Clanguage;
};
struct xinxi
{
int num;
int ave;
char name[15];
char sex;
struct fengshu score;
};
average(int a, int b, int c, int d)
{
int sum=0;
float ave;
sum=a+b+c+d;
ave=sum/4.0;
return(ave);
}

main()
{
int i,j;
struct xinxi s[N];
struct xinxi t;
for(i=0;i
{
   printf("请输入第%d个同学的信息:\n",i+1);
   printf("姓名:");
   gets(s[i].name);

    printf("语文，数学，英语和C语言的成绩（中间用空格分开）:");
    scanf("%d %d%d%d",&s[i].score.chinese,&s[i].score.math,&s[i].score.english,&s[i].score.Clanguage);
   getchar();
   }
  }
for(i=0;i
   s[i].ave=average(s[i].score.chinese,s[i].score.math,s[i].score.english,s[i].score.Clanguage);
for(i=0;i<N;i++)
  for(j=i+1;j<N;j++)
     if(s[i].ave>s[j].ave)
       {
          t=s[i];
          s[i]=s[j];
          s[j]=t;
       }
   printf("按平均分排序为:\n");
  for(i=0;i<N;i++)
    printf("学号:%d 姓名:%s 性别:%c 语文,数学,英语,C语言成绩:%d %d %d%d   平均成绩:%d \n",s[i].num,s[i].name,s[i].sex,s[i].score.chinese,s[i].score.math,s[i].score.english,s[i].score.Clanguage,s[i].ave);
}

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