[LeetCode]Valid Number

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Validate if a given string is numeric.

Some examples:
"0" => true
" 0.1 " => true
"abc" => false
"1 a" => false
"2e10" => true

Note: It is intended for the problem statement to be ambiguous. You should gather all requirements up front before implementing one.

6e6.5不是数，这里指数不能为小数，但是理论上应该是可以的， 3e3.0也不是数

public class Solution {   public boolean isNumber(String s) {    String strim=s.trim();    if(strim.length()==0) return false;    if(strim.charAt(0)=='e'||strim.charAt(strim.length()-1)=='e') return false;    String strs[] = strim.split("e");    if(strs.length>2) return false;    for(int i=0;i<strs.length;i++){    String string = strs[i];    int spot = 0;    int num = 0;    if(string.length()==1&&(string.charAt(0)=='+'||string.charAt(0)=='-')) return false;    for(int j=0;j<string.length();j++){    char c = string.charAt(j);    if(c=='.'){        if(i==1) return false;    spot++;    }else if(c>'9'||c<'0'){    if(j==0&&(c=='-'||c=='+')) continue;    return false;    }else{     num++;    }    }    if(num==0||spot>1) return false;    String li[] = string.split("\\.");    if(li.length==0||li.length>2) return false;    }    return true;    }}

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