火爆的一乐面馆

来源:互联网 发布:四班三倒排班表软件 编辑:程序博客网 时间:2024/04/28 09:35

<pre class="objc" name="code"><pre class="objc" name="code">#include<stdio.h>#define MAX 10int main(){     int lieshu,i,j;    double lamiantime,kaoroutime,yinliaotime,time,temp;     double timetotal[MAX];     char str[MAX][18];     printf("请输入现在队伍的列数:\n");     scanf("%d",&lieshu);     if(lieshu>MAX)     { 
        printf("输入错误!!!\n"); 
        return 0;   
    }
        printf("拉面的制作时间:\n");        scanf("%lf",&lamiantime);   
        printf("烤肉的制作时间:\n");         scanf("%lf",&kaoroutime);        printf("饮料的制作时间:\n");         scanf("%lf",&yinliaotime);         for(i=0;i<lieshu;)         {               printf("第%d对的排列情况:\n",i+1);               scanf("%s",str[i]); i++; }               for(i=0;i<lieshu;i++)              {
                     time=0;
                     for(j=0;str[i][j]!='\0';j++)                     {
                             if(str[i][j]=='a'||str[i][j]=='A')                                     time+=kaoroutime+yinliaotime;                              else if(str[i][j]=='b'||str[i][j]=='B')                                     time+=2*kaoroutime+2*lamiantime;                              else if(str[i][j]=='c'||str[i][j]=='C')                                     time+=3*kaoroutime+3*lamiantime+3*yinliaotime;                             else 
                             {
                                               printf("输入错误!!!\n");
                                               return 0; 
                             }
                       }                                      timetotal[i]=time; 
                     }                      for(i=0;i<lieshu;i++)                      { 
                             for(j=1;j<lieshu;j++)                              { 
                                     if(timetotal[i]>timetotal[j])                                      {              
                                               temp=timetotal[i]; 
                                               timetotal[i]=timetotal[j];
                                               timetotal[j]=temp;                                      }                              }                     }         printf("鸣人所需最短时间:%.2lf\n",timetotal[0]);        return 0;}



 

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