生活中的数学问题（四）

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/**************************************** *  File Name  : math.c *  Creat Data : 2015.1.24*  Author     : ZY *****************************************/ /*生活中的数学问题*//*假设银行整存整取存款不同期限的月息利率分别为：0.63%    期限 = 1年0.66%    期限 = 2年0.69%    期限 = 3年0.75%    期限 = 5年0.84%    期限 = 8年利息 = 本金*月息利率*12*存钱年限。现在某人手中有2000元，请通过计算选择一种存钱方案，使得钱存进银行20年后得到的利息最多（假定银行对超过存款期限的那部分时间不付利息）*/#include <stdio.h>#include <math.h>int main(){int i8,i5,i3,i2,i1,n8,n5,n3,n2,n1;float temp,max = 0.0;for( i8 = 0 ;i8 < 3;i8++ ){for( i5 = 0 ;i5 <= (20 - i8*8)/5;i5++ ){for( i3 = 0;i3 <= (20 - i8*8 - i5*5)/3 ;i3++ ){for( i2 = 0;i2 <= (20 - i8*8 - i5*5 - i3*3)/2;i2++ ){i1 = 20 - i8*8 - i5*5 - i3*3 -i2*2;temp = 2000.0*pow((double)(1+0.0063*12),(double)i1)*pow((double)(1+2*0.0066*12),(double)i2)*pow((double)(1+3*0.0069*12),(double)i3)*pow((double)(1+5*0.0075*12),(double)i5)*pow((double)(1+8*0.0084*12),(double)i8);if( temp > max ){max = temp;n1 = i1;n2 = i2;n3 = i3;n5 = i5;n8 = i8;}}}}}printf("   For maxinum profit,he should so save his money in a bank:\n");printf("          made fixed deposit for 1 year:%d times\n",n1);printf("          made fixed deposit for 2 year:%d times\n",n2);printf("          made fixed deposit for 3 year:%d times\n",n3);printf("          made fixed deposit for 5 year:%d times\n",n5);printf("          made fixed deposit for 8 year:%d times\n",n8);printf("                                  Total:%.1f\n",max);return 0;}
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