一段H264数据的分析



         

       

目录(?)[-]

1. 分析00 00 00 01 67 42 00 1E 99 A0 B1 31 00 00 00 01
2. 分析00 00 00 01 68 CE 38 80 00 00 00 01

 

分析00 00 00 01 67 42 00 1E 99 A0 B1 31 00 00 00 01

H264的数据流分为两种，一种是NAL UNIT stream(RTP),一种是 bits stream,
两者可以互相转换。我们分析的这个是 bit stream,根据Annex B
00 00 00 01 67 42 00 1E 99 A0 B1 31 是 一个NAL，在两个00 00 00 01之间
0110 0111 0100 0010 0000 0000 0001 1110 1001 1001 1010 0000 1011 0001 0011 0001
forbidden_zero_bit（1） ＝ 0
nal_ref_idc（2）＝ 11
nal_unit_type（5） ＝ 0 0111：seq_parameter_set_rbsp( )
所以 processSPS

0110 0111 0100 0010 0000 0000 0001 1110 1001 1001 1010 0000 1011 0001 0011 0001
profile_idc(8):42：0100 0010

0110 0111 0100 0010 0000 0000 0001 1110 1001 1001 1010 0000 1011 0001 0011 0001

constraint_set0_flag(1):0
constraint_set1_flag(1):0
constraint_set2_flag(1):0
constraint_set3_flag(1):0
reserved_zero_4bits(4):0
0110 0111 0100 0010 0000 0000 0001 1110 1001 1001 1010 0000 1011 0001 0011 0001

level_idc(8):1E
seq_parameter_set_id(UE(V)):
ue(v): unsigned integer Exp-Golomb-coded syntax element with the left bit first. The parsing process for this descriptor is specified in subclause 9.1
uvlC: 1001：根据Table9.1 ， value= 0,只占1bit.
根据profile_idc忽略掉一部分。
log2_max_frame_num_minus4(ue(v): 001 10,len = 5,value= 5
pic_order_cnt_type(ue(v)):01 1,len = 3,value = 2
根据pic_order_cnt_type忽略几个参数
num_ref_frames（ue）：010,len = 3,value = 1

0110 0111 0100 0010 0000 0000 0001 1110 1001 1001 1010 0000 1011 0001 0011 0001
gaps_in_frame_num_value_allowed_flag(1) = 0
pic_width_in_mbs_minus1(ue):000 1011 ,len = 7,value = 10;
pic_height_in_map_units_minus1(ue):0001 001,len = 7,value = 8
frame_mbs_only_flag(1) = 1
忽略1
direct_8x8_inference_flag（1）:0
忽略
vui_parameters_present_flag(1):0
忽略
NALU结束

分析00 00 00 01 68 CE 38 80 00 00 00 01

0110 1000(68)
forbidden_zero_bit（1） ＝ 0
nal_ref_idc（2）＝ 11
nal_unit_type（5） ＝01000：pic_parameter_set_rbsp( ),7.3.2.2
1100 (C)
pic_parameter_set_id (ue)=0
seq_parameter_set_id(ue)=0
entropy_coding_mode_flag(1) :0, 重要的flag,0 表示编码Exp-Golomb coded and CAVLC,1表示CABAC
pic_order_present_flag(1):0
1110 (E)
num_slice_groups_minus1(ue):0
忽略
num_ref_idx_l0_active_minus1（ue）:0
num_ref_idx_l1_active_minus1(ue):0
weighted_pred_flag(1);0
0011 1000 1000 0000 (38 80)
weighted_bipred_idc(2):00
pic_init_qp_minus26 /* relative to 26 */(se):0
pic_init_qs_minus26 /* relative to 26 */(se):0
chroma_qp_index_offset(se):0
deblocking_filter_control_present_flag(1);0
constrained_intra_pred_flag(1):0
redundant_pic_cnt_present_flag(1):0
忽略
NALU结束

65 88 80 21 71 27 1B 88…….3888*16 byte
65：0110 0101
forbidden_zero_bit（1） ＝ 0
nal_ref_idc（2）＝ 11
nal_unit_type（5） ＝0 0101：slice_layer_without_partitioning_rbsp( ),IDR浈
Slice
Slice_Header:
first_mb_in_slice(ue):0
slice_type(ue):000 1000 = 7
pic_parameter_set_id(ue) = 0
80 21：000 0000 0010 0001
frame_num(u(v): frame_num is used as an identifier for pictures and shall be represented by log2_max_frame_num_minus4 + 4 bits,9 bits = 0
忽略
if( nal_unit_type = = 5 ) //IDR frame
idr_pic_id(u(e)):0
忽略N多
ref_pic_list_reordering( ) 见7。3。3。1忽略，Islice,SI slice,B slice
nal_ref_idc   =11 所以dec_ref_pic_marking( )
nal_unit_type = 5，所以
no_output_of_prior_pics_flag（1）：0
long_term_reference_flag（1）：0
忽略
。。71 27
001 0111 0001 0010 0111
slice_qp_delta（se（v）：001 01 ，4：-2
忽略

slice_data( ):7.3.4
对I-Slice:忽略N多
进入if( moreDataFlag ) { if( MbaffFrameFlag && ( CurrMbAddr % 2 = = 0 | |                  ( CurrMbAddr % 2 = = 1 && prevMbSkipped ) ) )mb_field_decoding_flag
macroblock_layer( )}
mb_field_decoding_flag忽略
macroblock_layer( )
mb_type（ue（v）：0
mb_pred( mb_type )
prev_intra4x4_pred_mode_flag[ luma4x4BlkIdx ] （1bit, 对babac是ae(v)）:1
1 27:0001 0010 0111
prev_intra4x4_pred_mode_flag[ 1 ] : 0001,0,001
0010 0111
prev_intra4x4_pred_mode_flag[ 2 ] : 0010,0,010
prev_intra4x4_pred_mode_flag[ 3] : 0111,0,111
……16个
1b 88 00 3e cf. 
intra_chroma_pred_mode（ue(v)） : 最后的一个1bit:0

接下来是macroblock_layer的coded_block_pattern和run level,既系数
c0 06 ad a0 18
1100 0000 0000 0110 1010 0000 0001 1000
coded_block_pattern（me(v):0,根据，= 47，0x2f
mb_qp_delta(se(v):0 len =1
residual( )见7.3.5.3
residual_block( LumaLevel[ i8x8 * 4 + i4x4 ], 16 )
coeff_token(ce(v): 00 0000 0000 0110 1
nc = 0(left block and top block 相关的)：

len: {   // 0702

{ 1, 6, 8, 9,10,11,13,13,13,14,14,15,15,16,16,16,16},

{ 0, 2, 6, 8, 9,10,11,13,13,14,14,15,15,15,16,16,16},

{ 0, 0, 3, 7, 8, 9,10,11,13,13,14,14,15,15,16,16,16},

{ 0, 0, 0, 5, 6, 7, 8, 9,10,11,13,14,14,15,15,16,16},

},

{

{ 2, 6, 6, 7, 8, 8, 9,11,11,12,12,12,13,13,13,14,14},

{ 0, 2, 5, 6, 6, 7, 8, 9,11,11,12,12,13,13,14,14,14},

{ 0, 0, 3, 6, 6, 7, 8, 9,11,11,12,12,13,13,13,14,14},

{ 0, 0, 0, 4, 4, 5, 6, 6, 7, 9,11,11,12,13,13,13,14},

},

{

{ 4, 6, 6, 6, 7, 7, 7, 7, 8, 8, 9, 9, 9,10,10,10,10},

{ 0, 4, 5, 5, 5, 5, 6, 6, 7, 8, 8, 9, 9, 9,10,10,10},

{ 0, 0, 4, 5, 5, 5, 6, 6, 7, 7, 8, 8, 9, 9,10,10,10},

{ 0, 0, 0, 4, 4, 4, 4, 4, 5, 6, 7, 8, 8, 9,10,10,10},

},

code:

{ 1, 5, 7, 7, 7, 7,15,11, 8,15,11,15,11,15,11, 7,4},

{ 0, 1, 4, 6, 6, 6, 6,14,10,14,10,14,10, 1,14,10,6},

{ 0, 0, 1, 5, 5, 5, 5, 5,13, 9,13, 9,13, 9,13, 9,5},

{ 0, 0, 0, 3, 3, 4, 4, 4, 4, 4,12,12, 8,12, 8,12,8},

},

{

{ 3,11, 7, 7, 7, 4, 7,15,11,15,11, 8,15,11, 7, 9,7},

{ 0, 2, 7,10, 6, 6, 6, 6,14,10,14,10,14,10,11, 8,6},

{ 0, 0, 3, 9, 5, 5, 5, 5,13, 9,13, 9,13, 9, 6,10,5},

{ 0, 0, 0, 5, 4, 6, 8, 4, 4, 4,12, 8,12,12, 8, 1,4},

},

{

{15,15,11, 8,15,11, 9, 8,15,11,15,11, 8,13, 9, 5,1},

{ 0,14,15,12,10, 8,14,10,14,14,10,14,10, 7,12, 8,4},

{ 0, 0,13,14,11, 9,13, 9,13,10,13, 9,13, 9,11, 7,3},

{ 0, 0, 0,12,11,10, 9, 8,13,12,12,12, 8,12,10, 6,2},

},
根据表查的：
code = 13,len = 15，i= 12，j=2
所以numcoeff = 12,numtrailingones = 2
010 0000 0001 1000: totalzeros:根据numcoeff

int lentab[TOTRUN_NUM][16] =

{

 

{ 1,3,3,4,4,5,5,6,6,7,7,8,8,9,9,9},

{ 3,3,3,3,3,4,4,4,4,5,5,6,6,6,6},

{ 4,3,3,3,4,4,3,3,4,5,5,6,5,6},

{ 5,3,4,4,3,3,3,4,3,4,5,5,5},

{ 4,4,4,3,3,3,3,3,4,5,4,5},

{ 6,5,3,3,3,3,3,3,4,3,6},

{ 6,5,3,3,3,2,3,4,3,6},

{ 6,4,5,3,2,2,3,3,6},

{ 6,6,4,2,2,3,2,5},

{ 5,5,3,2,2,2,4},

{ 4,4,3,3,1,3},

{ 4,4,2,1,3}, numcoeff开始

{ 3,3,1,2},

{ 2,2,1},

{ 1,1},

};

int codtab[TOTRUN_NUM][16] =

{

{1,3,2,3,2,3,2,3,2,3,2,3,2,3,2,1},

{7,6,5,4,3,5,4,3,2,3,2,3,2,1,0},

{5,7,6,5,4,3,4,3,2,3,2,1,1,0},

{3,7,5,4,6,5,4,3,3,2,2,1,0},

{5,4,3,7,6,5,4,3,2,1,1,0},

{1,1,7,6,5,4,3,2,1,1,0},

{1,1,5,4,3,3,2,1,1,0},

{1,1,1,3,3,2,2,1,0},

{1,0,1,3,2,1,1,1,},

{1,0,1,3,2,1,1,},

{0,1,1,2,1,3},

{0,1,1,1,1}, numcoeff开始

{0,1,1,1},

{0,1,1},

{0,1},

};