将list转换成json

来源:互联网 发布:macbook运行java 编辑:程序博客网 时间:2024/06/05 22:46
有好多好用的工具,今天小编给大家推荐个fastjson.jar.简单的将list集合转换成json数组。
在项目 pom文件中增加
<!-- json转换工具 -->
<dependency>
<groupId>com.alibaba</groupId>
<artifactId>fastjson</artifactId>
<version>1.1.37</version>
</dependency>
不是maven 项目的话,直接将fastjspn.jar 放入项目的lib目录中即可。

以下是测试类:

package com.wd.health.api.controller;

import java.util.ArrayList;
import java.util.List;
import com.alibaba.fastjson.JSON;
import com.wd.health.sdk.customer.model.CustPhone;


public class test {
public static void main(String[] args) {
CustPhone custPhone = new CustPhone();
custPhone.setCustId(1231);
custPhone.setDesc("231321sda");
custPhone.setId(213);
custPhone.setIsDefault(1);
custPhone.setIsEnable(1);
custPhone.setPhone("21321");
List<CustPhone> list = new ArrayList<CustPhone>();
for (int i = 0; i < 3; i++) {
list.add(custPhone);
}
System.out.println(JSON.toJSON(list).toString());
}
}

输出结果为:
[{"custId":1231,"desc":"231321sda","id":213,"isDefault":1,"isEnable":1,"phone":"21321"},{"custId":1231,"desc":"231321sda","id":213,"isDefault":1,"isEnable":1,"phone":"21321"},{"custId":1231,"desc":"231321sda","id":213,"isDefault":1,"isEnable":1,"phone":"21321"}]

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