uva 699 The Falling Leaves (二叉树)
来源:互联网 发布:java 动态方法 编辑:程序博客网 时间:2024/05/01 11:26
uva 699 The Falling Leaves
Each year, fall in the North Central region is accompanied by the brilliant colors of the leaves on the trees, followed quickly by the falling leaves accumulating under the trees. If the same thing happened to binary trees, how large would the piles of leaves become?
We assume each node in a binary tree "drops" a number of leaves equal to the integer value stored in that node. We also assume that these leaves drop vertically to the ground (thankfully, there's no wind to blow them around). Finally, we assume that the nodes are positioned horizontally in such a manner that the left and right children of a node are exactly one unit to the left and one unit to the right, respectively, of their parent. Consider the following tree:
The nodes containing 5 and 6 have the same horizontal position (with different vertical positions, of course). The node containing 7 is one unit to the left of those containing 5 and 6, and the node containing 3 is one unit to their right. When the "leaves" drop from these nodes, three piles are created: the leftmost one contains 7 leaves (from the leftmost node), the next contains 11 (from the nodes containing 5 and 6), and the rightmost pile contains 3. (While it is true that only leaf nodes in a tree would logically have leaves, we ignore that in this problem.)
Input
The input contains multiple test cases, each describing a single tree. A tree is specified by giving the value in the root node, followed by the description of the left subtree, and then the description of the right subtree. If a subtree is empty, the value-1 is supplied. Thus the tree shown above is specified as 5 7 -1 6 -1 -1 3 -1 -1. Each actual tree node contains a positive, non-zero value. The last test case is followed by a single-1 (which would otherwise represent an empty tree).Output
For each test case, display the case number (they are numbered sequentially, starting with 1) on a line by itself. On the next line display the number of "leaves" in each pile, from left to right, with a single space separating each value. This display must start in column 1, and will not exceed the width of an 80-character line. Follow the output for each case by a blank line. This format is illustrated in the examples below.Sample Input
5 7 -1 6 -1 -1 3 -1 -18 2 9 -1 -1 6 5 -1 -1 12 -1-1 3 7 -1 -1 -1-1
Sample Output
Case 1:7 11 3Case 2:9 7 21 15
题目大意:每个叶子在垂直方向落叶,最后垂直和是多少。
#include <stdio.h>#include<string.h>int tree[100], L, R;void build(int num, int pos) {int x, y;if (num != -1) {if (pos < L) L = pos;if (pos > R) R = pos;tree[pos] += num;scanf("%d", &x);build(x, pos - 1);scanf("%d", &y);build(y, pos + 1);}}int main() {int i, n, sum = 0;while (scanf("%d", &n) && n != -1) {memset(tree, 0, sizeof(tree));sum++;L = 50; R = 50;build(n, 50);printf("Case %d:\n", sum);for (i = L ;i < R; i++)printf("%d ", tree[i]);printf("%d\n\n", tree[R]);}return 0;}
- Uva 699 - The Falling Leaves//二叉树
- UVA - 699 The Falling Leaves 二叉树
- uva 699 The Falling Leaves 二叉树
- uva 699 The Falling Leaves (二叉树)
- Uva-699 - The Falling Leaves(二叉树与递归)
- UVA 699The Falling Leaves(二叉树)
- UVA 699 The Falling Leaves(二叉树|DFS)
- UVa 699 - The Falling Leaves 二叉树的落叶
- UVa 699 The Falling Leaves (DFS遍历二叉树)
- UVA 699 The Falling Leaves (二叉树水题)
- UVA 399 The Falling Leaves(二叉树)
- uva 699 The Falling Leaves(建二叉树同时求和)
- The Falling Leaves 下落的树叶 UVA 699(二叉树)
- uva 699 The Falling Leaves(建树)
- uva 699 - The Falling Leaves
- uva 699 The Falling Leaves
- uva 699 - The Falling Leaves
- UVa 699 - The Falling Leaves
- c#一次上传多个文件的写法
- 使用C#获取CPU及硬盘序列号的源代码
- 人脸识别系统原理
- CUDA系列学习(四)Parallel Task类型 与 Memory Allocation
- 书籍下架情况分析
- uva 699 The Falling Leaves (二叉树)
- 学术休假----求二次方程的根
- three.js 源码注释(八十七)extras/FontUtils.js
- linux查找包装grep脚本
- OpenCV学习篇之二 播放视频
- POJ 3080 Blue Jeans
- banner图片轮转(利用jquery)
- 工作纪要---解决统计差别问题
- iOS-target/action模式,delegate模式