九度 题目1010：A + B

处理好字符串即可。代码：

#include <iostream>#include <string>#include <map>using namespace std;map<string, int> dict;string str;int a, b;void init(){dict["zero"] = 0;dict["one"] = 1;dict["two"] = 2;dict["three"] = 3;dict["four"] = 4;dict["five"] = 5;dict["six"] = 6;dict["seven"] = 7;dict["eight"] = 8;dict["nine"] = 9;}int string_to_int(const string& str){int ret = 0;for (size_t i=0, next=str.find(' '); next!=string::npos; i=next+1, next=str.find(' ',i)){ret = 10 * ret + dict[str.substr(i, next-i)];}return ret;}int main(){init();while (getline(cin, str)){int plus_index = str.find('+');int equal_index = str.find('=');a = string_to_int(str.substr(0, plus_index));b = string_to_int(str.substr(plus_index+2, equal_index-plus_index-2));if (a + b != 0){cout << a + b << endl;} else {break;}}return 0;}