uva10391
来源:互联网 发布:俄罗斯地狱之门 知乎 编辑:程序博客网 时间:2024/05/16 05:49
思路:把单词切割成两部分,在set中查找是否两部分都存在即可
package test;import java.util.Scanner;import java.util.TreeSet;public class Test{static TreeSet<String> set1 = new TreeSet<String>();public static void main(String[] args) {Scanner sc = new Scanner(System.in);String line = null;System.out.println("input:");while(!"".equals((line=sc.nextLine().toLowerCase()))){set1.add(line);}sc.close();for(String word:set1){for(int i=0,len=word.length();i<len;i++){String pre = word.substring(0,i);String last = word.substring(i,len);if(set1.contains(pre)&&set1.contains(last)){System.out.println(word);break;}}}}}
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