MongoDB基本语法详解

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1、查询所有记录
db.userInfo.find();

相当于:select* from userInfo;

2、查询去掉后的当前聚集集合中的某列的重复数据
db.userInfo.distinct("name");
会过滤掉name中的相同数据
相当于:select distict name from userInfo;
 
3、查询age = 22的记录
db.userInfo.find({"age": 22});
相当于: select * from userInfo where age = 22;
 
4、查询age > 22的记录
db.userInfo.find({age: {$gt: 22}});
相当于:select * from userInfo where age >22;
 
5、查询age < 22的记录
db.userInfo.find({age: {$lt: 22}});
相当于:select * from userInfo where age <22;
 
6、查询age >= 25的记录
db.userInfo.find({age: {$gte: 25}});
相当于:select * from userInfo where age >= 25;
 
7、查询age <= 25的记录
db.userInfo.find({age: {$lte: 25}});
 
8、查询age >= 23 并且 age <= 26
db.userInfo.find({age: {$gte: 23, $lte: 26}});
 
9、查询name中包含 mongo的数据
db.userInfo.find({name: /mongo/});
//相当于%%
select * from userInfo where name like ‘%mongo%’;
 
10、查询name中以mongo开头的
db.userInfo.find({name: /^mongo/});
select * from userInfo where name like ‘mongo%’;
 
11、查询指定列name、age数据
db.userInfo.find({}, {name: 1, age: 1});
相当于:select name, age from userInfo;
当然name也可以用true或false,当用ture的情况下河name:1效果一样,如果用false就是排除name,显示name以外的列信息。
 
12、查询指定列name、age数据, age > 25
db.userInfo.find({age: {$gt: 25}}, {name: 1, age: 1});
相当于:select name, age from userInfo where age >25;
 
13、按照年龄排序
升序:db.userInfo.find().sort({age: 1});
降序:db.userInfo.find().sort({age: -1});
 
14、查询name = zhangsan, age = 22的数据
db.userInfo.find({name: 'zhangsan', age: 22});
相当于:select * from userInfo where name = ‘zhangsan’ and age = ‘22’;
 
15、查询前5条数据
db.userInfo.find().limit(5);
相当于:selecttop 5 * from userInfo;
 
16、查询10条以后的数据
db.userInfo.find().skip(10);
相当于:select * from userInfo where id not in (
selecttop 10 * from userInfo
);
 
17、查询在5-10之间的数据
db.userInfo.find().limit(10).skip(5);
可用于分页,limit是pageSize,skip是第几页*pageSize
 
18、or与 查询
db.userInfo.find({$or: [{age: 22}, {age: 25}]});
相当于:select * from userInfo where age = 22 or age = 25;
 
19、查询第一条数据
db.userInfo.findOne();
相当于:selecttop 1 * from userInfo;
db.userInfo.find().limit(1);
 
20、查询某个结果集的记录条数
db.userInfo.find({age: {$gte: 25}}).count();
相当于:select count(*) from userInfo where age >= 20;
 
21、按照某列进行排序
db.userInfo.find({sex: {$exists: true}}).count();
相当于:select count(sex) from userInfo;
索引
1、创建索引
db.userInfo.ensureIndex({name: 1});
db.userInfo.ensureIndex({name: 1, ts: -1});
 
2、查询当前聚集集合所有索引
db.userInfo.getIndexes();
 
3、查看总索引记录大小
db.userInfo.totalIndexSize();
 
4、读取当前集合的所有index信息
db.users.reIndex();
 
5、删除指定索引
db.users.dropIndex("name_1");
 
6、删除所有索引索引
db.users.dropIndexes();

 修改、添加、删除集合数据

1、添加
db.users.save({name: ‘zhangsan’, age: 25, sex: true});
添加的数据的数据列,没有固定,根据添加的数据为准
 
2、修改
db.users.update({age: 25}, {$set: {name: 'changeName'}}, false, true);
相当于:update users set name = ‘changeName’ where age = 25;
 
db.users.update({name: 'Lisi'}, {$inc: {age: 50}}, false, true);
相当于:update users set age = age + 50 where name = ‘Lisi’;
 
db.users.update({name: 'Lisi'}, {$inc: {age: 50}, $set: {name: 'hoho'}}, false, true);
相当于:update users set age = age + 50, name = ‘hoho’ where name = ‘Lisi’;
 
3、删除
db.users.remove({age: 132});
 
4、查询修改删除
db.users.findAndModify({
    query: {age: {$gte: 25}}, 
    sort: {age: -1}, 
    update: {$set: {name: 'a2'}, $inc: {age: 2}},
    remove: true
});
 
db.runCommand({ findandmodify : "users", 
    query: {age: {$gte: 25}}, 
    sort: {age: -1}, 
    update: {$set: {name: 'a2'}, $inc: {age: 2}},
    remove: true
});

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