tomcat-servlet-AJAX最基础例子

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index.html

name:<input type="text" id="namevalue"><br><button id="btn">发送</button>结果:<span id="result"></span>

$(document).ready(function () {    $("#btn").click(function () {      /*  $.get("*.*",{name:$("#namevalue").val()}, function (data) {//服务器            $("#result").text(data);        });*/    $("#result").text("正在连接服务器...");        $.post("/HTML/servlet/serv1",{name:$("#namevalue").val()}, function (data) {            $("#result").text(data);        }).error(function () {//连接服务器出问题            $("#result").text("连接服务器失败!");        });    });});

web.xml

<?xml version="1.0" encoding="UTF-8"?><web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:jsp="http://java.sun.com/xml/ns/javaee/jsp"xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5">  <servlet>    <servlet-name>serv1</servlet-name>    <servlet-class>servlet.serv1</servlet-class>  </servlet>  <servlet-mapping>    <servlet-name>serv1</servlet-name>    <url-pattern>/servlet/serv1</url-pattern>  </servlet-mapping> </web-app>

servlet:

package servlet;import java.io.IOException;import javax.servlet.ServletException;import javax.servlet.http.HttpServlet;import javax.servlet.http.HttpServletRequest;import javax.servlet.http.HttpServletResponse;public class serv1 extends HttpServlet {public serv1() {super();}public void destroy() {super.destroy(); }public void doGet(HttpServletRequest request, HttpServletResponse response)throws ServletException, IOException {doPost(request,response);}public void doPost(HttpServletRequest request, HttpServletResponse response)throws ServletException, IOException {String name = request.getParameter("name");if(name.length()>0){response.getWriter().print("Hello! "+name);}else{response.getWriter().print("please enter your name!");}}public void init() throws ServletException {}}

打包代码下载:http://download.csdn.net/detail/oyuemijindu/8444127

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