USACO section2.3 Zero Sum题解&代码
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只需要按位数搜索,记录sum为0的情况
优先度为’ ‘>’+’>’-‘,需要记录的是之前位数可以计算出的值la和当前被操作的数no,下一个被操作数为p,当前位数后的符号即为s[p]
需要注意的一些小细节是在不加入操作符增加no时no>=0?no*10+p:no*10-p,在添加’-‘后下一个操作数将会是-p
/*ID:rainbow16LANG:C++TASK:zerosum*/#include<stdio.h>int n;char s[10];void dfs(int la,int no,int p){ if(p==n+1) { if(la+no==0) for(int i=1;i<=n;i++) printf("%d%c",i,s[i]); return; } s[p-1]=' '; dfs(la,no>=0?no*10+p:no*10-p,p+1); s[p-1]='+'; dfs(la+no,p,p+1); s[p-1]='-'; dfs(la+no,-p,p+1);}int main(void){ freopen("zerosum.in","r",stdin); freopen("zerosum.out","w",stdout); scanf("%d",&n); s[n]='\n'; dfs(0,1,2); return 0;}
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