aoj.339.Large or small

Large or small

Description

Only Input and Output

Input

Several cases.
A letter indicating the operation('L' means to output the lager one while 'S' the smaller).
Followed by two integers. It's guaranteed that all numbers are smaller than 10^5.

Output

According to the operation to output the lager or smaller integer on a seperate line.
If the letter is not 'L' or 'S' just print "Input error!".

Sample Input

L 3 4S 3 4

Sample Output

43

法一：清理缓存法

#include"stdio.h"
int main()
{
    char ch;
    long x,y;
    while(scanf("%c",&ch)!=EOF)
    {
        scanf("%ld %ld",&x,&y);
        if(ch=='L')
            printf("%ld\n",x>y?x:y);
        else if(ch=='S')
            printf("%ld\n",y>x?x:y);
        else
            printf("Input error!\n")
        fflush(stdin);       /*清理缓存，清除上次执行命令的换行*//*aoj无法通过？？*/
    }
    return 0；
｝
法二：当输入换行时执行下次循环，去除关于换行的代入执行
#include"stdio.h"  
int main() 
{ 
    char ch; 
    long x,y; 
    while(scanf("%c",&ch)!=EOF) 
    { 
        if(ch=='\n')             /*判断读入的是否为换行符*//*换行符来自上次最后键入的命令*/
            continue;               /*是则结束本次循环*/
        scanf("%ld %ld",&x,&y); 
        if(ch=='S') 
            printf("%ld\n",x<y?x:y); 
        else if(ch=='L') 
            printf("%ld\n",x>y?x:y); 
        else
            printf("Input error!\n"); 
    }  
    return 0; 
}