uva_644

来源:互联网 发布:java replace 编辑:程序博客网 时间:2024/06/05 08:14

这道题比较水,早上起来a了他,感觉价值不大。。。

代码如下

#include <stdio.h>#include <string.h>#include <stdlib.h>int isD(char* s, char* t){    int i, lens, lent;    lens = strlen(s);    lent = strlen(t);    i = 0;    while(s[i] == t[i] && i < lens && i < lent){        i++;    }    if(i == lens || i == lent) return 1;    return 0;}int main(){    int i, j, k, state, ta;    char cod[8][15];    char ch[15];    ta = 0;    i = 0;    state = 0;    while(scanf("%s", ch) != EOF){        if(strcmp(ch, "9")){            strcpy(cod[i++], ch);        }        else{            ta++;            k = i;            for(i = 0; i < k; ++i){                for(j = i + 1; j < k; ++j){                    if(isD(cod[i], cod[j])) state = 1;                }            }            if(!state) printf("Set %d is immediately decodable\n", ta);            else printf("Set %d is not immediately decodable\n", ta);            memset(cod, 0, sizeof(cod));            i = 0;            state = 0;        }    }    return 0;}


0 0
原创粉丝点击