UVa814 - The Letter Carrier's Rounds

来源：互联网发布：南方电网大数据编辑：程序博客网时间：2024/05/21 11:17
终于感觉到一个简单的题
#include<iostream>#include<string>#include<vector>#include<set>#include<map>using namespace std;void parse_address(const string& s, string& user, string& mta){    int k = s.find('@');    user = s.substr(0, k);    mta = s.substr(k+1);}int main(){    int k;    string s, t, user1, mta1, user2, mta2;    set<string> addr;    while(cin >> s && s != "*"){        cin>>s>>k;        while(k--) { cin>>t; addr.insert(t+"@"+s); }    }    while(cin>>s&&s!="*"){        parse_address(s, user1, mta1);        vector<string> mta;        map<string, vector<string> >dest;        set<string> vis;        while(cin>>t && t!="*"){            parse_address(t, user2, mta2);            if(vis.count(t)) continue;            vis.insert(t);            if(!dest.count(mta2)) { mta.push_back(mta2); dest[mta2]=vector<string>(); }            dest[mta2].push_back(t);        }        getline(cin,t);        string data;        while(getline(cin,t) && t[0]!='*') data += ("     " + t + "\n");        for(int i=0;i<mta.size();i++){            string mta2=mta[i];            vector<string> users = dest[mta2];            cout<<"Connection between "<<mta1<<" and "<<mta2<<endl;            cout<<"     HELO "<<mta1<<"\n"; cout<<"     250\n";            cout<<"     MAIL FROM:<"<<s<<">\n";cout<<"     250\n";            bool ok=false;            for(int i=0;i<users.size();i++){                cout<<"     RCPT TO:<"<<users[i]<<">\n";                if(addr.count(users[i])) { ok=true; cout<<"     250\n"; }                else cout<<"     550\n";            }            if(ok){                cout<<"     DATA\n";cout<<"     354\n";                cout<<data;                cout<<"     .\n"; cout<<"     250\n";            }            cout<<"     QUIT\n"; cout<<"     221\n";        }    }    return 0;}
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