一些线程相关的问题

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题目：

8个运动员同时起跑，都到达终点后记录成绩

实现：

package com.spring.test;import java.util.Random;import java.util.concurrent.CountDownLatch;/** * Created by brady on 15-3-1. */public class CountDownLatchTest implements Runnable{    private int id;    private CountDownLatch beginSingnal;    private CountDownLatch endSingnal;    public CountDownLatchTest(int id ,CountDownLatch beginSingnal,CountDownLatch endSingnal){        this.id = id;        this.beginSingnal = beginSingnal;        this.endSingnal = endSingnal;    }    @Override    public void run(){        try{            beginSingnal.await();            Random random = new Random();            Thread.sleep(Math.abs(random.nextInt())%100);            endSingnal.countDown();            System.out.println("我到了：" + this.id);        }catch (InterruptedException e){            e.printStackTrace();        }    }    public static void main(String[] args){        CountDownLatch beginSingnal = new CountDownLatch(1);        CountDownLatch endSingnal = new CountDownLatch(8);        for(int i=1;i<=8;i++){            new Thread(new CountDownLatchTest(i,beginSingnal,endSingnal)).start();        }        beginSingnal.countDown();        try {            endSingnal.await();        } catch (InterruptedException e) {            e.printStackTrace();        }    }}

两个线程循环打印

package com.spring.test;/** * Created by brady on 15-3-13. *//* * 两个线程循环打印 */public class WaitNotify {    private static final Object a = new Object();    private static boolean x1 = true;    private static boolean y1 = false;    private static final int x = 30;    private static int y = 1;    public static void main(String[] args){        Thread t1 = new Thread(){            public void run(){                synchronized (a){                    while (!x1) try {                        a.wait();                    } catch (InterruptedException e) {                        e.printStackTrace();                    }                    while (y<x){                        for(int i=0;i<3;i++){                            System.out.println("线程一：" + y++);                        }                        x1=false;                        y1=true;                        a.notify();                    }                }            }        };        Thread t2 = new Thread(){            public void run(){                synchronized (a){                    while (!y1) try {                        a.wait();                    } catch (InterruptedException e) {                        e.printStackTrace();                    }                    while (y<x){                        for(int i=0;i<3;i++){                            System.out.println("线程二：" + y++);                        }                        y1=false;                        x1=true;                        a.notify();                    }                }            }        };        t1.start();        t2.start();    }}

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