Codeforces Round #295 A. Pangram
来源:互联网 发布:淘宝红包雨从哪里找 编辑:程序博客网 时间:2024/05/22 09:55
标准水题一枚,先全部转化成小写,然后用个数组做个统计,看看是不是26个字母全有了就行了。
package com.codeforces.algorithm;import java.io.PrintWriter;import java.util.*;public class Pangram {public static void main(String []args){Scanner cin = new Scanner(System.in);PrintWriter cout = new PrintWriter(System.out);while(cin.hasNext()){int n = cin.nextInt();String str = cin.next();String ptr = str.toLowerCase();int []num = new int[27];for(int i=0;i<27;i++) num[i]=0;for(int i=0;i<ptr.length();i++){num[ptr.charAt(i)-'a']++;}boolean flag=true;for(int i=0;i<26;i++){if(num[i]==0){flag=false;break;}}if(flag){cout.println("YES");}else{cout.println("NO");}cout.flush();}cout.close();}}
0 0
- Codeforces Round #295 A. Pangram
- Codeforces Round #295 A. Pangram
- Codeforces Round #295 (Div. 2) -- A. Pangram
- Codeforces Round #295 (Div. 2) A. Pangram
- Codeforces Round #295 (Div. 2), problem: (A) Pangram
- Codeforces Pangram
- A Pangram
- A. Pangram
- Codeforces #295(Div 2) A Pangram、B Two Buttons、C DNA Alignment
- codeforces——520A——Pangram
- 520A Pangram【implement】
- Pangram
- Codeforces Round #295 (Div. 1) (A B)
- Codeforces Round #295 (Div. 2) A、B
- codeforces round#283 A
- Codeforces Round #234A
- Codeforces Round #439 A
- codeforces div2 round#231 A
- C#生成随机数的三种方法
- PAT A1084或者B1029 旧键盘
- HTTP协议理解与应用总结
- iOS性能优化:Instruments使用实战
- UIKit框架-高级控件:6.UIPickerView与UIImageView结合使用
- Codeforces Round #295 A. Pangram
- Gesture Recognizer(添加手势)
- 搭建自己的git 代码服务器
- 求婚大作战 豆瓣 影评
- Mac osx 下安装 Java
- Analyze静态分析
- PAT 1001. A+B Format (20)
- try/throw/catch
- SQLAlchemy 和其他的 ORM 框架