1028. List Sorting
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Excel can sort records according to any column. Now you are supposed to imitate this function.
Input
Each input file contains one test case. For each case, the first line contains two integers N (<=100000) and C, where N is the number of records and C is the column that you are supposed to sort the records with. Then N lines follow, each contains a record of a student. A student's record consists of his or her distinct ID (a 6-digit number), name (a string with no more than 8 characters without space), and grade (an integer between 0 and 100, inclusive).
Output
For each test case, output the sorting result in N lines. That is, if C = 1 then the records must be sorted in increasing order according to ID's; if C = 2 then the records must be sorted in non-decreasing order according to names; and if C = 3 then the records must be sorted in non-decreasing order according to grades. If there are several students who have the same name or grade, they must be sorted according to their ID's in increasing order.
#include <stdio.h>#include <stdlib.h>#include <string.h>#include <vector>#include <algorithm>using namespace std;typedef struct{ char id[8],name[10]; int grade; }Student;bool cmp1 (Student a,Student b);bool cmp2 (Student a,Student b);bool cmp3 (Student a,Student b);vector<Student> student;int main (){ int num,column; scanf("%d %d",&num,&column); int i; Student temp; for( i=0;i<num;i++) { scanf("%s %s %d",temp.id,temp.name,&temp.grade); student.push_back(temp); } switch (column) { case 1:sort(student.begin(),student.end(),cmp1);break; case 2:sort(student.begin(),student.end(),cmp2);break; case 3:sort(student.begin(),student.end(),cmp3);break; } for( i=0;i<num;i++) { printf("%s %s %d\n",student[i].id,student[i].name,student[i].grade); } system("pause"); return 0; }bool cmp1 (Student a,Student b){ return strcmp(a.id,b.id)<0; }bool cmp2 (Student a,Student b){ if (strcmp(a.name,b.name)!=0) return strcmp(a.name,b.name)<0; else return cmp1(a,b); }bool cmp3 (Student a,Student b){ if( a.grade!=b.grade) return a.grade<b.grade; else return cmp1(a,b); }
- 1028. List Sorting (25)
- 1028. List Sorting
- 1028. List Sorting (25)
- 1028. List Sorting (25)
- PAT 1028. List Sorting
- 1028. List Sorting
- 1028. List Sorting
- 1028. List Sorting (25)
- 1028. List Sorting (25)
- 1028. List Sorting (25)
- 1028. List Sorting (25)
- 1028.List Sorting
- 1028. List Sorting (25)
- 1028. List Sorting (25)
- 1028. List Sorting
- 1028. List Sorting (25)
- 1028. List Sorting (25)
- 1028. List Sorting (25)
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