*LeetCode-Remove Duplicates from Sorted Array
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蠢哭了要 还想着每次遇到重复都把整个数组移一遍，不用啊！两个指针一个在现在无重复区域的末尾，一个在还没判断的区域的头，只要不一样就挪这一位，一样就不管，最后返回无重复区域的index＋1不就是length勒马
public class Solution { public int removeDuplicates(int[] A) { if ( A == null || A.length == 0 ) return 0; int pos = 1; for ( int i = 1; i < A.length; i ++ ){ if ( A [i] != A [pos-1] ){ A [pos] = A[i]; pos ++; } } return pos; }} 0 0
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