Java RMI AccessControlException: access denied



http://docs.oracle.com/javase/tutorial/rmi/client.html

http://docs.oracle.com/javase/tutorial/rmi/running.html

java -cp c:\home\ann\src;c:\home\ann\public_html\classes\compute.jar
     -Djava.rmi.server.codebase=file:/c:/home/ann/public_html/classes/compute.jar
     -Djava.rmi.server.hostname=mycomputer.example.com
     -Djava.security.policy=server.policy
        engine.ComputeEngine

Java RMI AccessControlException: access denied

http://stackoverflow.com/questions/2427473/java-rmi-accesscontrolexception-access-denied

had a simliar problem with that connection exception. it is thrown either when the registry is not started yet (like in your case) or when the registry is already unexported (like in my case).

but a short comment to the difference between the 2 ways to start the registry:

Runtime.getRuntime().exec("rmiregistry 2020");

runs the rmiregistry.exe in javas bin-directory in a new process and continues parallel with your java code.

LocateRegistry.createRegistry(2020);

the rmi method call starts the registry, returns the reference to that registry remote object and then continues with the next statement.

in your case the registry is not started in time when you try to bind your object

Rmi connection refused with localhost

http://stackoverflow.com/questions/1823305/rmi-connection-refused-with-localhost

I've been stuck on this all day (after figuring out I had to start the rmiregistry from the commandline), trying to make this work locally with Eclipse, and finally solved it. A few pointers to save others this cruel fate:

1 - assign the policy file correctly, either with a commandline flag:

java -Djava.security.policy=/home/.../<filename>.policy ...

or by putting this directly in your code:

System.setProperty("java.security.policy","file:///home/.../<filename>.policy");

You can also put it in the same folder as your project root), to reduce the URI to

file:./<filename>.policy

(use a relative instead of absolute URI - I actually didn't understand this until today).

2 - make sure the format of the policy file is correct, e.g.:

grant codeBase "file:<path>/bin/-" {    permission java.security.AllPermission;};

This should refer to the folder where your binary is located! A thorough explanation of the format of the policy file ishere.

That's about it, I'd also recommend this tutorial, I found it very helpful to get on the right track.

running rmi server, classnotfound

http://stackoverflow.com/questions/464687/running-rmi-server-classnotfound

The exception is occurring because the rmiregistry application doesn't know where to load classes from. When you attempt to bind an object in the RMI registry, the registry downloads the class definition for that object. Some of the other answers are telling you to get around this by setting the classpath for the rmiregistry app so that it has the class definitions when it is started and doesn't need to download anything, but Sun's Java RMI tutorialexplicitly says not to do this. I suspect this has the potential to cause conflicts between the version of the class in the registry and the class on the server.

The correct way to handle the problem is to set the java.rmi.server.codebase property as you were trying to do. The property requires that a directory path be terminated with a forward slash, like so:

-Djava.rmi.server.codebase=file:${workspace_loc}/progInternet2008/

You may also be having trouble if the ${workspace_loc} variable is a relative path and the rmiregistry application was not started in the same directory so the relative path is not correct for it. If you either make the path absolute, or start the rmiregistry in the appropriate directory, the ClassNotFoundException should go away. See thetutorial on the java.rmi.server.codebase property for a little more detailed information.