POJ1001--Exponentiation(幂计算)翻译
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Total Submissions: 141868Accepted: 34673
Description
描述
Problems involving the computation of exact values of very large magnitude and precision are common.
高精度、大数值的计算问题是很常见的,
For example, the computation of the national debt is a taxing experience for many computer systems.
比如:国债的计算。
This problem requires that you write a program to compute the exact value of Rn where R is a real number ( 0.0 < R < 99.999 ) and n is an integer such that 0 < n <= 25.
现在要求你写一个程序精确计算Rn,其中R是一个实数(0.0 < R < 99.999),n是一个整数,且0 < n <= 25
Input
输入
The input will consist of a set of pairs of values for R and n.
输入包含多组R、n。
The R value will occupy columns 1 through 6, and the n value will be in columns 8 and 9.
R占第1到6列,n占第8到9列。
Output
输出
The output will consist of one line for each line of input giving the exact value of R^n.
对于每组输入,其输出占一行,输出值为R^n。
Leading zeros should be suppressed in the output. Insignificant trailing zeros must not be printed.
不要输出第一位的0,末尾无意义的0也不用输出。
Don't print the decimal point if the result is an integer.
如果结果为整数则不用输出小数部分
Sample Input
95.123 12
0.4321 20
5.1234 15
6.7592 9
98.999 10
1.0100 12
Sample Output
548815620517731830194541.899025343415715973535967221869852721
.00000005148554641076956121994511276767154838481760200726351203835429763013462401
43992025569.928573701266488041146654993318703707511666295476720493953024
29448126.764121021618164430206909037173276672
90429072743629540498.107596019456651774561044010001
1.126825030131969720661201
Hint
提示
If you don't know how to determine wheather encounted the end of input:
如果你不知道如何判定输入是否结束:
s is a string and n is an integer
s是字符串,n是整数。
C++
while(cin>>s>>n)
{
...
}
c
while(scanf("%s%d",s,&n)==2) //to see if the scanf read in as many items as you want
/*while(scanf(%s%d",s,&n)!=EOF) //this also work */
{
...
}
Source
East Central North America 1988
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参考:http://zhidao.baidu.com/link?url=Hw2b3JjT9lRBQx2V28ZGARQBVm4pUrPJ_tZSWvgB0qU1IOxbVYBKYWumKCbP1mnwGEzb3_LVK3iQneDftdepVa
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