LeetCode:Convert Sorted Array to Binary Search Tree
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一次AC,很常规的递归调用。
class Solution {public: TreeNode *sortedArrayToBST(vector<int> &num) {//递归算法,取中间数为根节点,两边的数组递归调用构造左子树和右子树 if(num.empty())//如果为空,则返回空子树 return NULL; TreeNode *root; if(num.size()==1)//如果只有一个结点,则直接初始化结点返回 { root=new TreeNode(num[0]); return root; } int mid; mid=num.size()/2; root=new TreeNode(num[mid]); root->left=sortedArrayToBST(num,0,mid-1); root->right=sortedArrayToBST(num,mid+1,num.size()-1); return root; }private: TreeNode *sortedArrayToBST(vector<int> &num,int m,int n)//m,n分别为起始下标,终点下标 { if(n<m)//元素为空 return NULL; TreeNode *root; if(n==m)//只有一个元素 { root=new TreeNode(num[n]); return root; } int mid; mid=m+(n-m)/2; root=new TreeNode(num[mid]); root->left=sortedArrayToBST(num,m,mid-1); root->right=sortedArrayToBST(num,mid+1,n); return root; }};
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