常用字符串hash算法
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以前学习数据结构中有关hash部分的时候一带而过,现在真正在实践中用到的时候才感受到hash的魅力。HDOJ1800可作为练习
以下是常用字符串hash算法的简单对比分析:
注:
其中数据1为100000个字母和数字组成的随机串哈希冲突个数。数据2为100000个有意义的英文句子哈希冲突个数。数据3为数据1的哈希值与1000003(大素数)求模后存储 到线性表中冲突的个数。数据4为数据1的哈希值与10000019(更大素数)求模后存储到线性表中冲突的个数。
// RS Hash Functionunsigned int RSHash(char* str){ unsigned int b = 378551; unsigned int a = 63689; unsigned int hash = 0; while(*str){ hash = hash * a + (*str++); a *= b; } return (hash & 0x7FFFFFFF);}// JS Hash Functionunsigned int JSHash(char* str){ unsigned int hash = 1315423911; while(*str) hash ^= ((hash << 5) + (*str++) + (hash >> 2)); return (hash & 0x7FFFFFFF);}// P. J. Weinberger Hash Functionunsigned int PJWHash(char* str){ unsigned int BitsInUnignedInt = (unsigned int )( sizeof (unsigned int)*8); unsigned int ThreeQuarters = (unsigned int )((BitsInUnignedInt*3 ) / 4); unsigned int OneEighth = (unsigned int )(BitsInUnignedInt / 8); unsigned int HighBits = (unsigned int )( 0xFFFFFFFF ) << (BitsInUnignedInt - OneEighth); unsigned int hash = 0; unsigned int test = 0; while(*str){ hash = (hash << OneEighth) + (*str++); if((test = hash & HighBits) != 0) hash = ((hash ^ (test >> ThreeQuarters)) & ( ~ HighBits)); } return (hash & 0x7FFFFFFF);}// ELF Hash Functionunsigned int ELFHash(char* str){ unsigned int hash = 0; unsigned int x = 0; while(*str){ hash = (hash << 4 ) + (*str ++ ); if((x = hash & 0xF0000000L ) != 0 ){ hash ^= (x >> 24 ); hash &= ~ x; } } return (hash & 0x7FFFFFFF);}// BKDR Hash Functionunsigned int BKDRHash(char* str){ unsigned int seed = 131; // 31 131 1313 13131 131313 etc.. unsigned int hash = 0; while(*str) hash = hash*seed + (*str ++ ); return (hash & 0x7FFFFFFF);}// SDBM Hash Functionunsigned int SDBMHash(char* str){ unsigned int hash = 0; while(*str) hash = (*str ++ ) + (hash << 6 ) + (hash << 16 ) - hash; return (hash & 0x7FFFFFFF);}// DJB Hash Functionunsigned int DJBHash(char* str){ unsigned int hash = 5381; while(*str) hash += (hash << 5 ) + (*str ++ ); return (hash & 0x7FFFFFFF);}// AP Hash Functionunsigned int APHash(char* str){ unsigned int hash = 0; int i; for(i = 0 ;*str; i ++ ){ if((i & 1 ) == 0 ) hash ^= ((hash << 7 ) ^ (*str ++ ) ^ (hash >> 3 )); else hash ^= ( ~ ((hash << 11 ) ^ (*str ++ ) ^ (hash >> 5 ))); } return (hash & 0x7FFFFFFF);}
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