LeetCode OJ Find Minimum in Rotated Sorted Array

Suppose a sorted array is rotated at some pivot unknown to you beforehand.

(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).

Find the minimum element.

You may assume no duplicate exists in the array.

class Solution {public:    int findMin(vector<int> & num) {        if (num.size() == 1) return num[0];        if (num[0] < num[1] && num[0] < num[num.size() - 1]) return num[0];        return num[findGap(num)];    }    int findGap(vector<int> & num) {        int l = 0, h = num.size() - 1;        while (l <= h) {            if (l == h - 1) return h;            int m = (l + h) / 2;            if (num[l] > num[m]) {                h = m;            } else if (num[m] > num[h]) {                l = m;            }        }        return -1;    }};