Shell分割迭代字符串

问题：

IN=”www:wangliang:hello”以冒号分隔，读取分割的内容www,wangliang和hello。

解答

前言

如果是是一空格（空白）为分隔符，下面是一种解决方案：

sentence="This is a sentence."for word in $sentencedo        echo $worddone

如果是要求直接读取，不迭代，下面是一种解决方案：
line=www:wangliang:hello
read p1 p2 p3 <<<(IFS=":";echoline)
echo p1, p2, p3

---

以下是多种方法：

solution 1

IFS=':' read -ra ADDR <<< "$IN"#printf "%s\n" "${ADDR[@]}"#echo "[" ${ADDR[0]} "]" "[" ${ADDR[1]} "]" "[" #${ADDR[2]} "]"for i in "${ADDR[@]}"; do    echo $idone

solution 2

for i in $(echo $IN | tr ":" "\n")do  echo $idone

solution 3

arrIN=(${IN//:/ })# printf "%s\n" "${arrIN[@]}"echo "[" ${arrIN[0]} "]" "[" ${arrIN[1]} "]" "[" ${arrIN[2]} "]"

solution 4

echo $IN | sed -e 's/:/\n/g'

solution 5

read ADDR1 ADDR2 ADDR3 <<<$(IFS=":"; echo $IN)echo $ADDR1 "----" $ADDR2 "---" $ADDR3