杭电 HDU 1076 An Easy Task

An Easy Task

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 16217    Accepted Submission(s): 10363

Problem Description

Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?

Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.

Note: if year Y is a leap year, then the 1st leap year is year Y.

 

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains two positive integers Y and N(1<=N<=10000).

 

Output

For each test case, you should output the Nth leap year from year Y.

 

Sample Input

32005 251855 122004 10000

 

Sample Output

2108190443236
Hint
We call year Y a leap year only if (Y%4==0 && Y%100!=0) or Y%400==0.
 

 

Author

Ignatius.L

 

#include<iostream>using namespace std;int main(){int T;int Y,N;cin>>T;while(T--){int number=0;int i;cin>>Y>>N;for( i=Y;;i++){if(number==N)break;elseif(((i%4==0)&&(i%100!=0))||(i%400==0))number++;}cout<<i-1<<endl;}return 0;}