有趣的编码累加问题 Encoding 【水】
来源:互联网 发布:淘宝提升关键词排名 编辑:程序博客网 时间:2024/06/05 00:39
Encoding
Time Limit: 1 Sec Memory Limit: 32 MBSubmit: 23 Solved: 8
[Submit][Status][Web Board]
Description
Given a string containing only 'A' - 'Z', we could encode it using the following method:
1. Each sub-string containing k same characters should be encoded to "kX" where "X" is the only character in this sub-string.
2. If the length of the sub-string is 1, '1' should be ignored.
Input
The first line contains an integer N (1 <= N <= 100) which indicates the number of test cases. The next N lines contain N strings. Each string consists of only 'A' - 'Z' and the length is less than 10000.
Output
For each test case, output the encoded string in a line.
Sample Input
2ABCABBCCC
Sample Output
ABCA2B3C
HINT
Source
#include <stdio.h>#include <iostream>using namespace std;const int MAX = 10001;int main(){int n;int i,j;char x[MAX];char c;while(~scanf("%d",&n)){while ( n-- ){cin >> x;i = 0, j = 1;while( x[i] != '\0'){if ( x[i] == x[ i + 1]){j++;i++;}else {c = x[i];if ( j == 1){cout << c;i++; }else { cout << j;cout << c;i++;j = 1;} }} cout << endl;}}return 0;}
这么水的题目 居然上传错了几次 什么鬼。。。。。
0 0
- 有趣的编码累加问题 Encoding 【水】
- 有趣的累加求和实现
- encoding编码问题
- 字符串编码(charset,encoding/decoding)问题原理
- 字符串编码(charset, encoding/decoding)问题原理
- 字符串编码(charset, encoding/decoding)问题原理
- 字符串编码(charset, encoding/decoding)问题原理
- NSString自带的的方法URL encoding的编码问题
- SyntaxError:Non-ASCII character ,……no encoding declared. --python 中文处理的编码问题
- VIM的编码相关,encoding, filecoding, termencoding
- VIM的编码相关,encoding, filecoding, termencoding
- xml的encoding与文件编码关系
- 邮件编码Content-Transfer-Encoding的各种形式?
- VIM的编码相关,encoding, filecoding, termencoding
- transfer-encoding: chunked的问题
- Console的默认Encoding问题
- 一个有趣的盛水问题
- 有趣的问题
- java基础加强(类加载器)
- C++中文件按行读取和逐词读取
- JavaScript DOM 学习(1) Hello World
- 初识java
- synchronized notify wait的用法
- 有趣的编码累加问题 Encoding 【水】
- 核心板大作-Freescale IMX6Q出炉(WePower6Q)
- 最简便的apk混淆方法
- windows 下 java jar程序的运行
- [BZOJ2878][Noi2012]迷失游乐园 && 树形DP
- 利用java反射机制打印类的信息
- The struts dispatcher cannot be found
- C++中读入一行字符的操作
- 结构-02. 有理数加法(15)