c++ 与 lua函数互调

来源：互联网发布：剧本写作软件编辑：程序博客网时间：2024/06/06 16:41

// TestLua.cpp : 定义控制台应用程序的入口点。//#include "stdafx.h"#include <string>#include <iostream>extern "C"{#include "lua.h"#include "lualib.h"#include "lauxlib.h"};using namespace std;lua_State* L;//接口方法static int Lua_Average(lua_State* lua){int n = lua_gettop(lua);  //返回战中元素的个数float sum = 0;int i = 1;for(i; i <= n; i++){if(!lua_isnumber(lua, i)){lua_pushstring(L,"**** there has a error, argument has not number");lua_error(lua);}sum += lua_tonumber(lua, i);}lua_pushnumber(lua, sum/n);   //将数值返回lualua_pushnumber(lua, sum);return 2;}int _tmain(int argc, _TCHAR* argv[]){//初始化luaL = luaL_newstate();luaL_openlibs(L);//函数注册lua_register(L,"Average", Lua_Average);//加载lua脚本， 脚本放在工程目录下luaL_loadfile(L, "testA.lua");int dwError = lua_pcall(L, 0 ,LUA_MULTRET,0);if(dwError != 0){cout<<lua_tostring(L,-1);lua_close(L);return 1;}lua_getglobal(L, "avg");cout<<"avg is "<<lua_tostring(L, -1) << endl;lua_pop(L, 1);lua_getglobal(L,"sum");cout<<"sum = "<<lua_tointeger(L,-1)<<endl;lua_pop(L, 1);//调用 lua中的函数int a = 10;int b = 11;lua_getglobal(L,"SumFunc");lua_pushinteger(L,a);lua_pushinteger(L,b);int dwRet = lua_pcall(L,2,1,0);if(dwRet != 0){cout<<lua_tostring(L, -1);lua_pop(L,1);return 0;}printf("sum: %d + %d = %ld\n", a,b,lua_tointeger(L,-1));lua_pop(L,-1);//调用结束，清除Lua lua_close(L);return 0;}

Lua 脚本

function SumFunc( a, b)<span style="white-space:pre"></span>return a + b;endavg, sum = Average(10, 20, 30, 40, 50)print("The average is ", avg)print("The sum is ", sum)

注：

1. c++中的函数注册最好是在lua脚本加载之前完成注册，否则lua 文件如果在加载后就调用c++中的函数时会报错

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