hdu-1865-1sting(大数问题)

1sting

Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 3870    Accepted Submission(s): 1463

Problem Description

You will be given a string which only contains ‘1’; You can merge two adjacent ‘1’ to be ‘2’, or leave the ‘1’ there. Surly, you may get many different results. For example, given 1111 , you can get 1111, 121, 112,211,22. Now, your work is to find the total number of result you can get.

 

Input

The first line is a number n refers to the number of test cases. Then n lines follows, each line has a string made up of ‘1’ . The maximum length of the sequence is 200.

 

Output

The output contain n lines, each line output the number of result you can get .

 

Sample Input

311111111

 

Sample Output

128

 

Author

z.jt

 

Source

2008杭电集训队选拔赛——热身赛

 

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按字符串长度递推，然后2的n次方是个大数

/* * http://acm.hdu.edu.cn/showproblem.php?pid=1865 * by jtahstu on 2015/3/31 14:00 */package 大数;import java.math.BigInteger;import java.util.Scanner;public class HDU1865 {public static Scanner cin = new Scanner(System.in);public static void main(String[] args) {// TODO 自动生成的方法存根int n = cin.nextInt();BigInteger a[] = new BigInteger[201];a[1] = BigInteger.valueOf(1);a[2] = BigInteger.valueOf(2);for (int i = 3; i <= 200; i++)a[i] = a[i - 1].add(a[i - 2]);//递推，只是这是大数while (n-- > 0) {String s;s = cin.next();int len = s.length();System.out.println(a[len]);}}}