做业1

习题2.29

#include<iostream>#include<iomanip>using namespace std; int main(){int i;int*p= new int[20];p[0]=1;     p[1]=1;      for(i=2;i<20;i++)         p[i]=p[i-2]+p[i-1];for(i=0;i<20;i++){if(i%3==0)cout<<endl;cout<<setw(8)<<*(p+i);}cout<<endl;   return 0; }

习题2.30

#include<iostream.h>#include<cmath>int scroot(int i){    return sqrt(i);}long scroot(long j){    return sqrt(j);}double scroot(double k){    return sqrt(k);}int main(){   int i=9;   long j=404040;   double k=6464.64;   cout<<"i的二次方根为"<<scroot(i)<<endl;   cout<<"j的二次方根为"<<scroot(j)<<endl;   cout<<"k的二次方根为"<<scroot(k)<<endl;   return 0;}