iOS —— Cell + UIMenuController

实现长按弹出菜单栏需要做3点：

1.在view（cell）或者viewController中调用-becomeFirstResponder方法；

2.你的view获得或者view controller需要实现 -canBecomeFirstResponder 方法,返回YES;

3.你的view获得或者view controller需要实现-canPerformAction:action withSender:sender 方法来隐藏或者现实响应的item；

cell中关键代码展示：

1.添加长安事件

[self addGestureRecognizer: [[UILongPressGestureRecognizer alloc]initWithTarget:self action:@selector(longTap:)]];

2.处理长按事件

-(void)longTap:(UILongPressGestureRecognizer *)longRecognizer{if (longRecognizer.state==UIGestureRecognizerStateBegan) {[self becomeFirstResponder];UIMenuController *menu=[UIMenuController sharedMenuController];UIMenuItem *copyItem = [[UIMenuItem alloc] initWithTitle:@"复制"action:@selector(copyItemClicked:)];UIMenuItem *resendItem = [[UIMenuItem alloc] initWithTitle:@"转发"action:@selector(resendItemClicked:)];[menu setMenuItems:[NSArray arrayWithObjects:copyItem,resendItem,nil]];[menu setTargetRect:self.bounds inView:self];[menu setMenuVisible:YES animated:YES];}}

3.实现默认方法

#pragma mark 处理action事件-(BOOL)canPerformAction:(SEL)action withSender:(id)sender{if(action ==@selector(copyItemClicked:)){return YES;}else if (action==@selector(resendItemClicked:)){return YES;}return [super canPerformAction:action withSender:sender];}#pragma mark 实现成为第一响应者方法-(BOOL)canBecomeFirstResponder{return YES;}

4.处理item点击事件

#pragma mark method-(void)resendItemClicked:(id)sender{NSLog(@"转发");//通知代理}-(void)copyItemClicked:(id)sender{NSLog(@"复制");// 通知代理 }