[LeetCode] Spiral Matrix II
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Spiral Matrix II
Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order.
For example,
Given n = 3
,
[ [ 1, 2, 3 ], [ 8, 9, 4 ], [ 7, 6, 5 ]]
解题思路:
http://blog.csdn.net/kangrydotnet/article/details/44727955的姐妹篇。不停的进行扫描而已。注重分析能力。
源代码:
class Solution {public: vector<vector<int> > generateMatrix(int n) { int** d=new int*[n]; for(int i=0; i<n; i++){ d[i] = new int[n]; } int x=0, y=0; int data=1; while(data<=n*n){ //赋值上边 for(int i=y; i < n-y; i++){ d[x][i] = data; data++; } //赋值右边 for(int i=x+1; i< n-x; i++){ d[i][n-y-1]=data; data++; } //赋值下边 for(int i=n-y-2; i>=y; i--){ d[n-x-1][i]=data; data++; } //赋值左边 for(int i=n-x-2; i>x; i--){ d[i][y] = data; data++; } x++; y++; } vector<vector<int>> result; for(int i=0; i<n; i++){ vector<int> row; for(int j=0; j<n; j++){ row.push_back(d[i][j]); } result.push_back(row); } for(int i=0; i<n; i++){ delete[] d[i]; } delete[] d; return result; }};
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