LeetCode Sort Colors
来源:互联网 发布:手机怎样在淘宝买东西 编辑:程序博客网 时间:2024/06/05 17:03
Given an array with n objects colored red, white or blue, sort them so that objects of the same color are adjacent, with the colors in the order red, white and blue.
Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively.
Note:
You are not suppose to use the library's sort function for this problem.
click to show follow up.
Follow up:
A rather straight forward solution is a two-pass algorithm using counting sort.
First, iterate the array counting number of 0's, 1's, and 2's, then overwrite array with total number of 0's, then 1's and followed by 2's.
Could you come up with an one-pass algorithm using only constant space?
题意:就是在数组A[]中,将0,1,2重新排序。
思路:计数排序或者三指针来做,一个指针指向放red的位置,一个指针指向blue的位置,然后就能依次放了,中间的没有处理的就都是白色的了
class Solution {public: void sortColors(int A[], int n) { if (A == NULL || n < 2) return; int num0 = 0, num1 = 0, num2 = 0; for (int i = 0; i < n; i++) { if (A[i] == 0) num0++; else if (A[i] == 1) num1++; else num2++; } int i = 0; while (num0--) A[i++] = 0; while (num1--) A[i++] = 1; while (num2--) A[i++] = 2; }};
class Solution {public: void sortColors(int A[], int n) { if (A == NULL || n < 2) return; int red = 0, blue = n-1; for (int i = red; i <= blue; i++) { if (A[i] == 0) swap(A[red++], A[i]); else if (A[i] == 2) swap(A[blue--], A[i--]); } }};
- LeetCode: Sort Colors
- LeetCode Sort Colors
- LeetCode : Sort Colors
- leetcode 77: Sort Colors
- Leetcode 75 Sort Colors
- leetcode 101: Sort Colors
- [LeetCode]Sort Colors
- [leetcode]Sort Colors
- LeetCode-Sort Colors
- [leetcode] Sort Colors
- [LeetCode] Sort Colors
- [leetCode] Sort Colors
- LeetCode - Sort Colors
- leetcode:Sort Colors
- LeetCode | Sort Colors
- 【LeetCode】Sort Colors
- Leetcode: Sort Colors
- [LeetCode] Sort Colors
- 二叉树--顺序结构
- 数组 Remove Duplicates from Sorted Array
- soapui+groovy进行接口自动化测试浅谈
- 蓝桥杯:第三十九级台阶
- Spring BlazeDS Integration Reference Guide
- LeetCode Sort Colors
- 44. PHP while
- 张伟平得罪巩俐:在张艺谋面前捏造其劈腿
- 蝶恋花
- 欢迎使用CSDN-markdown编辑器
- UPC:2218 Thrall’s Dream(BFS)
- ZooKeeper基础
- Video Google: A Text Retrieval Approach to Object Matching in Videos
- XSLT输出比较或运算不想被转义