LightOJ 1047 Neighbor House (DP 数字三角形变形)
来源:互联网 发布:mac 终端退出编辑 编辑:程序博客网 时间:2024/05/20 03:47
The people of Mohammadpur have decided to paint each oftheir houses red, green, or blue. They've also decided that no two neighboringhouses will be painted the same color. The neighbors of housei arehouses i-1 and i+1. The first and last houses are not neighbors.
You will be given the information of houses. Each house willcontain three integers"R G B" (quotes for clarity only),where R, G and B are the costs of painting the correspondinghouse red, green, and blue, respectively. Return the minimal total costrequired to perform the work.
Input
Input starts with an integer T (≤ 100),denoting the number of test cases.
Each case begins with a blank line and an integern (1≤ n ≤ 20) denoting the number of houses. Each of the next nlines will contain 3 integers "R G B". These integers will liein the range[1, 1000].
Output
For each case of input you have to print the case number andthe minimal cost.
Sample Input
Output for Sample Input
2
4
13 23 12
77 36 64
44 89 76
31 78 45
3
26 40 83
49 60 57
13 89 99
Case 1: 137
Case 2: 96
题目链接:http://lightoj.com/volume_showproblem.php?problem=1047
题目大意:相邻行不能取同一列的数字,从上往下路径最大权值和问题。
解题思路:只有三列,每步有两次选择,dp[i][j]表示到第a[i][j]步的最小数字累加和,起点处分三条路,最后选出和最小的一条路。
代码如下:
#include <cstdio>#include <cstring>int a[25][4],dp[25][4];int min2(int a,int b){ return a>b?b:a;}int min3(int a,int b,int c){ if(a<=b&&a<=c) return a; if(b<=a&&b<=c) return b; if(c<=b&&c<=a) return c;}int main(){ int t,n,i,j,cnt=0; scanf("%d",&t); while(t--) { int ans; memset(dp,0,sizeof(dp)); memset(a,0,sizeof(a)); scanf("%d",&n); for(i=0;i<n;i++) for(j=0;j<3;j++) scanf("%d",&a[i][j]); dp[0][0]=a[0][0]; dp[0][1]=a[0][1]; dp[0][2]=a[0][2]; for(i=1;i<n;i++) { dp[i][0]=a[i][0]+min2(dp[i-1][2],dp[i-1][1]); dp[i][1]=a[i][1]+min2(dp[i-1][2],dp[i-1][0]); dp[i][2]=a[i][2]+min2(dp[i-1][0],dp[i-1][1]); } ans=min3(dp[n-1][0],dp[n-1][1],dp[n-1][2]); printf("Case %d: %d\n",++cnt,ans); } return 0;}
- LightOJ 1047 Neighbor House (DP 数字三角形变形)
- LightOJ 1047 Neighbor House (DP 数字三角形变形)
- LightOJ 1047 Neighbor House (线性dp 类数字三角形)
- lightOJ 1047 Neighbor House (DP)
- LightOJ 1047 - Neighbor House(dp)
- LightOJ 1047 - Neighbor House (dp)
- LightOj 1047 Neighbor House(基础dp)
- 【LightOJ】1047 - Neighbor House(dp)
- LightOJ 1047 - Neighbor House 【DP】
- lightoj 1047 Neighbor House(Dp)
- LightOJ - 1047 Neighbor House(DP)
- LightOJ 1047 - Neighbor House(DP)
- lightoj 1047 - Neighbor House DP
- 【 lightoj 1047 - Neighbor House + dp】
- lightoj 1047 - Neighbor House DP(简单线性DP)
- lightoj-1047-Neighbor House【矩阵DP】
- LightOJ - 1217 Neighbor House (II)(dp)
- LightOJ 1047 - Neighbor House
- [libevent]Libevent介绍与编译
- vector的定义和初始化
- const int*和int* const
- Java内存分配和String类型的深度解析
- 常用控件
- LightOJ 1047 Neighbor House (DP 数字三角形变形)
- 二叉搜索树的详细实现
- 使用
- Eclipse使用入门教程
- 使用openFileInput和openfileOutput方法读写应用程序数据文件夹下的文件
- 伦敦的威斯敏斯特大教堂地下室的墓碑林中,一块震撼全世界的一段碑文。
- Android 应用程序获得系统权限
- 使用SharedPreferences读写配置信息
- Android监听连续点击次数代码实现