hdu 1212

Big Number

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 5551    Accepted Submission(s): 3856

Problem Description

As we know, Big Number is always troublesome. But it's really important in our ACM. And today, your task is to write a program to calculate A mod B.

To make the problem easier, I promise that B will be smaller than 100000.

Is it too hard? No, I work it out in 10 minutes, and my program contains less than 25 lines.

 

Input

The input contains several test cases. Each test case consists of two positive integers A and B. The length of A will not exceed 1000, and B will be smaller than 100000. Process to the end of file.

 

Output

For each test case, you have to ouput the result of A mod B.

 

Sample Input

2 312 7152455856554521 3250

 

Sample Output

251521

 

Author

Ignatius.L

 

Source

杭电ACM省赛集训队选拔赛之热身赛

 

可以用java也可用同余定理

#include<iostream>#include<cstdio>int main(){    char a[1001];    int b,i,r;    while(~scanf("%s%d",a,&b))    {        r=0;        for(i=0;a[i]!='\0';i++)        {            r=r*10+a[i]-'0';            r%=b;        }        printf("%d\n",r);    }    return 0;}